2a + 6b = c, where a, b, and c are all numbers from the domain of your choice.
Usually, in algebra, the real number set R is used as the domain.
In this case, you would need to select values from R for a and b which will yield the value of c. Since this function is closed in the real number system, c will always be a real number, given that a and b are real numbers.
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add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
6+7a+6b
12a + 6b + 6c = 6(2a + b + c)
Change the order to make it more obvious: 3a - a + 2b + 4b 2a + 6b or 2 (a + 3b).
a + a + a - 2a = 3a - 2a = a