2a + 6b = c, where a, b, and c are all numbers from the domain of your choice.
Usually, in algebra, the real number set R is used as the domain.
In this case, you would need to select values from R for a and b which will yield the value of c. Since this function is closed in the real number system, c will always be a real number, given that a and b are real numbers.
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
6+7a+6b
12a + 6b + 6c = 6(2a + b + c)
Change the order to make it more obvious: 3a - a + 2b + 4b 2a + 6b or 2 (a + 3b).
a + a + a - 2a = 3a - 2a = a
2a+6b
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
6(2a plus b)
6+7a+6b
2 x (2a + 3b - 6)
12a + 6b + 6c = 6(2a + b + c)
With the assumption your asking what a or b are in terms of each other. a=3b/(6b-2) b=2a/(6a-2)
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
Change the order to make it more obvious: 3a - a + 2b + 4b 2a + 6b or 2 (a + 3b).
11b + 6b = 17b
12a + 6b + 9a + 14b =(12a + 9a) + (6b + 14b) =21a + 20b
a + a + a - 2a = 3a - 2a = a