As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
fourteen take away four and then add a four and times by (2 times 4)
(44 - 4) / 4
How about: 44-(4/4) = 43
4 x 5 = 20.
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
to get 31 using the number 4 exactly 4 times, you can do: (4! + 4)/4 + 4!4! is four factorial, which is 4x3x2x1, which is 24. So you have 24 + 4 = 28, /4 = 7, + 24 = 31.
31 = 4! + 4 + (sqrt(4)/.4)
4+4-4=4
4!+(4+4!)/4
(42 + 42) - (4 / 4)
31 ÷ 9 = 3 remainder 4
fourteen take away four and then add a four and times by (2 times 4)
(44 - 4) / 4
How about: 44-(4/4) = 43
4 times 7.75 is 31.
4 x 5 = 20.