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How is average speed found using a distance vs time graph?
If it's the average speed of [a,b] where a is less than b, both are on the x axis (time), and both are in the domain of x then the equation is(f(b)-f(a))/(b-a)where f(b) is the distance when time=b and f(a) is the distance when time=a(?)
How do you work out b plus 9 equals 21?
b + 9 = 21 Take the + 9 across the other side of the equals sign. a plus becomes a minus. b = 21 - 9 so... b = 12. This can be checked by setting b to 12 in the first equation b + 9 = 21 12 + 9 = 21 which is correct.
In matrix multipliccation when does A plus B times A minus B equals A squared minus B squared?
All the time
Can you solve for b in the equation 12 equals negative 4 over 2 time negative 2 plus b?
12 = -4/2 * -2 + b 12 = -2 * -2 + b 12 = 4 + b 8 = b
A badge moves 8km per hour in still water it travels 6km upstream and 6 km downstream in a total time of 2 hours what is the speed of the current?
The speed upstream is B - C where B is the speed of the badge in still water and C is speed of the current The speed downstream is B + C. Velocity = Distance/Time : therefore Time = Distance/Velocity. Time for upstream journey = 6/(B - C) Time for downstream journey = 6/(B + C) BUT Total time for journey = 2 = 6/(B - C) + 6/(B + C) = 12B/(B2 - C2) Therefore 2B2 - 2C2 = 12B : However, B = 8kph so substituting gives, 128 - 2C2 = 96 : 2C2 = 32 : C2 = 16 : C = 4 The speed of the current is 4kph.
