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I guess you mean log2{log2[log2(x)]} = 0 ?

Let Y = {log2[log2(x)]}, so you have log2[Y] = 0

The solution to this is Y = 1,

Then you a simpler equation: log2[log2(x)] = 1

Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,

so log2(x) = 2, and x = 4

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