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A linear series with "i" terms can be summed by finding the average of the first and last terms, then multiplying by the amount of terms.This sequence can be written as follows:
ai= 11 + 1(i-1)
= 11 + i - 1
= 10 + i
11 is the first term, 1 is the difference between terms which gets multiplied by (i-1)
So the fourth term a4= 10 + 4 = 14
Sum total = i * (a1+ ai)/2 (no. of terms * average of first and last term)
= 10 * (11 + 20)/2
= 10 * (31/2)
= 155
What else can I help you with?
What is the a sum of 12 and a product of 11?
The sum of 12 and a product of 11 can be calculated by first finding the product of 12 and 11, which equals 132. Then, adding 12 to this product gives a sum of 144. Mathematically, this can be represented as 12 + (12 x 11) = 12 + 132 = 144.
What is the sum of 12 11?
23
What is the sum of1 11?
the answer is 12.
What is the sum of the factors of 11?
12.
How do I solve 11 12ths of 24?
To solve for 11/12 of 24, you first multiply 11/12 by 24. This can be done by converting 11/12 to a decimal (0.9167) and then multiplying it by 24. The result is approximately 22. The answer is that 11/12 of 24 is 22.
What is the sum of 11 plus 1?
12
What is one sixth plus three fourth?
The sum of 3/4 and 1/6 is 11/12
What is a multiple of 11 whose sum is 12?
66.
Factors of 66 with a sum of 12?
11 and 1
The sum of the consecutive number of 23?
11 and 12.
What two negative integers have a sum of -12 and a product of 11?
-11 and -1
If The sum of two factors of 11 is 12 what are the factors?
The factors are 1 & 11 !
