Don't bother. The statement isn't true. -7 is never equal to 5.
To express the quotient of ( x ) and 3 less than or equal to 5, you can write it as ( \frac{x}{3} \leq 5 ). This means that when you divide ( x ) by 3, the result must be less than or equal to 5. To solve for ( x ), you can multiply both sides by 3, yielding ( x \leq 15 ). Thus, ( x ) must be less than or equal to 15.
9>y≥5
times it
an integer that is greater than -5 but less than or equal to 9 is _______________. remember you need to answer it by yourself.
5
-2≤y≤5
equal to 5=5
Expressed algebraically, this is equal to 5x - 12.
9>y≥5
x is less than or equal to 6
times it
less
an integer that is greater than -5 but less than or equal to 9 is _______________. remember you need to answer it by yourself.
5
5
It is: b-5
less