Factors of numbers are divisible by them with no remainders
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Yes, you can. Using the divisibility rules, you can quickly tell that 87 is divisible by 3 (the digits add up to 15, which is divisible by 3). 3 x 29 = 87
Under todays rules: DXC
syntax
As a product of its prime factors: 3*5*7*7 = 735
As a product of its prime factors: 3*5*7*11 = 1155