If you have 4 DIFFERENT letters, there are 24 ways - this is equal to 4! (that is, the factorial of 4). Because of the two repeated letters, if you do this, you get every valid combination repeated twice (i.e., by exchanging one "a" with the other "a" you get an identical combination). Therefore the real number of arrangements is only one-half that value.
362,880 ways
15
Six.
There are 11!/[2!*2!*2!) = 4,989,600 ways.
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
mad adam dam am
362,880 ways
15
120 ways
Six.
There are 11!/[2!*2!*2!) = 4,989,600 ways.
120 different ways.
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
24 different ways (4! = 4 x 3 x 2 x 1)
There are 120 ways to order a 5 letter word, however, since there are two "e" letters in the word "green", the number of combinations is only 60.
There are 3360 ways.
It is 6!/3! = 6*5*4 = 120 ways