No. For example, if one angle measures 100 degrees, and its adjacent angle is 80 degrees, then the opposite angles would be either 200 or 160 degrees, but in order for a quadrilateral to be inscribed in a circle the opposite angles would have to equal 180 degrees. A parallelogram can be inscribed in a circle if it is a rectangle.
You would firstly have to know the mesurements of your triangle, including the height.. Then you do baseXheight divided by two... that gives you the square footage in the triangle. Then, you take one poit of your triangle as the center of your circle. The ray would be 7 metres. To get the square footage of a circle you have to do PIXsquareR...
The formula for area of a circle is Area=pi*radius2 you know the area of your circle so now find the radius. 154 = pi*r2 r = 7 cm if you can imagine the equilateral triangle in the circle imagine that the radius touches the exact center of this triangle and can extend to one of the three points on the triangle. (this next part would be so much easier if i could draw you a picture). now, if you remember that an equilateral triangle has three angles that each measure up to 60 degrees. if you take the radius of the circle and draw a line from the center of the triangle to the tip of the triangle you will actually cut on of the 60 degree angles in half. this would now make you have an angle 30 degrees. if you do this same thing to another point you will notice you actually have another triangle inside this triangle. since all triangle angles add up to 180 degrees you know all three angles of this new triangle. (note: this new triangle is not an equilateral triangle). so this new triangle has an angle 30 degrees, 30 degrees, and 120 degrees. you can now use the law of sines to find out the length of one side of the equilateral triangle. if you have drawn your picture correctly then you will see that one side of the new triangle actually shares one side of the equilateral triangle. if you look at your new triangle their is only one side that is known a known quantity. this side is the side that is shared with the equilateral triangle. use the law of sines to figure out the length of this side... 7 / sin(30) = x / sin(120) x = 12.12cm you now know that one side of the equlateral triangle is 12.12cm. since there is three sides to the triangle the total perimeter of the equilateral triange is 12.12 times 3 your answer for the perimeter of the equilateral triangle is 36.36cm
The best tool to locate the center of a circle would be a compass. By placing the compass on the edge of the circle and drawing an arc, then repeating this process from another point on the circle, the intersection point of the arcs will give you the center of the circle.
it would come down to the type of triangle.
It is its inradius.
The center of the circle inscribed in a triangle.
The center of the circle. Perhaps clarify the question?
The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.
There is a contradiction in the question. A circumscribed circle is the smallest circle that will contain the shape in question. For example, the circumcircle (circumscribing circle) of a triangle is the smallest one which will contain the triangle. However, the question refers to "within which the circle" which would imply an inscribed circle. This is the biggest circle that can be wholly enclosed within the shape in question. The two are obviously not the same and the question needs to be clear as to which one of the two is intended.
No. For example, if one angle measures 100 degrees, and its adjacent angle is 80 degrees, then the opposite angles would be either 200 or 160 degrees, but in order for a quadrilateral to be inscribed in a circle the opposite angles would have to equal 180 degrees. A parallelogram can be inscribed in a circle if it is a rectangle.
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The CIRCUMCENTER would be the correct fill in the blank for apex 2022 good luck
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The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
If I understand your question correctly, you would need to subtract the area of the inscribed circle from the circumscribed circle. Which would approximately be 78.60cm squared.
Looking from the base your would see a circle. Looking from the side you would see a triangle.