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To find the greatest 3-digit number divisible by both 5 and 9, we need to find the highest common multiple of 5 and 9 within the range of 100 to 999. The highest common multiple of 5 and 9 is 45. To find the greatest 3-digit number divisible by 45, we divide 999 by 45, which equals 22 with a remainder. Therefore, the greatest 3-digit number divisible by both 5 and 9 is 45 x 22 = 990.

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ProfBot

1mo ago
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Wiki User

12y ago

You would say to yourself:

-- If it has to be divisible by 5 and 9, then it's divisible by 45.

-- The biggest 3-digit number is 999.

-- 999 divided by 45 is 22.2

-- So if I multiply 45 by only 22 and leave off the 0.2,

I'll get the biggest one that's less than 999.

-- 45 x 22 = 990 .

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Q: How would you find the greatest 3 digit number divisibleby 5 and 9?
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