To find the greatest 3-digit number divisible by both 5 and 9, we need to find the highest common multiple of 5 and 9 within the range of 100 to 999. The highest common multiple of 5 and 9 is 45. To find the greatest 3-digit number divisible by 45, we divide 999 by 45, which equals 22 with a remainder. Therefore, the greatest 3-digit number divisible by both 5 and 9 is 45 x 22 = 990.
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You would say to yourself:
-- If it has to be divisible by 5 and 9, then it's divisible by 45.
-- The biggest 3-digit number is 999.
-- 999 divided by 45 is 22.2
-- So if I multiply 45 by only 22 and leave off the 0.2,
I'll get the biggest one that's less than 999.
-- 45 x 22 = 990 .
To determine which digit has the greatest value in a number, you would need to examine each digit individually and identify the highest one. For example, in the number 47382, the digit with the greatest value is 8. If you provide a specific number, I can help identify the greatest digit in that number.
I would think the greatest 7 digit number would be 9,999,999. Therefore if you add 1 more, you would get 10,000,000. Makes sense to me anyway, lol.
That would be 99987.
In order to make the number as big as possible, you would want the greatest value digits in the greatest place value. Thus the first number would have to be 9. Once 9 has been used, the second number would have to be 8. Then the third number would have to be 7 and so on. Therefore, the greatest 9 digit number with 9 different digits is 987,654,321.
There is no greatest number. Given any number with the digit 3 in the ten thousand place, it is always possible to add a billion (for example). That would still leave the 3 in the ten thousand place but would be a greater number.