If the object is small enough to place into a graduated container, note the level of the water and then totally immerse the object (being careful that no air bubbles remain under it) by pushing it just below the surface. Note the difference in the water level, and calculate the volume by multiplying the difference in water level times the area of the graduated container.
Half fill a graduated glass beaker with water and note the level. Place irregularly shaped object into the beaker. Note the new level. The difference between the two levels is the volume of the object. cw: OK, that method works for objects that don't get wet -- like steel. Tissue paper would not be a good candidate. Also, if the object floats, you have to submerge the object.
Mass divided by Volume = Density. Or use the displacement method for an irregularly shaped object.
If possible, fully immerse the object in water, and measure the volume of displaced water.
It is the displacement method.
Google "Archimedes' Principle" and see if that gives you a clue...
You can push it under water / under the liquid's surface, and measure the displacement of liquid.
You can find the volume of an irregularly shaped object, like a rock, by using the water displacement method. Submerge the object in a known volume of water in a container. Measure the increase in water level, which equals the volume of the rock.
One way to calculate the volume of an irregularly shaped object is by using the water displacement method. Submerge the object in a known volume of water and measure the change in volume to determine the object's volume.
The volume of an irregularly shaped geometric object is typically determined by the amount of water it displaces when submerged. This method utilizes the principle of fluid displacement to calculate the volume of the object. By measuring the amount of water the object displaces, one can determine its volume.
Half fill a graduated glass beaker with water and note the level. Place irregularly shaped object into the beaker. Note the new level. The difference between the two levels is the volume of the object. cw: OK, that method works for objects that don't get wet -- like steel. Tissue paper would not be a good candidate. Also, if the object floats, you have to submerge the object.
the water displacement method
When you are trying to find the volume of an irregularly shaped object.
Volume displacement.
Take an amount of water of which you know the volume. Drop the object in the water. Find the difference
The volume of the object is 7ml.
When an object is immersed in water the volume of water displaced is equal to the volume of that object as discovered by Archimedes.
Mass divided by Volume = Density. Or use the displacement method for an irregularly shaped object.