Once easy way is displacement. You can place it in liquid and see how much liquid it displaces. This will be the volume.
One way would be to get a container into which you could put the rock completely, fill it to the brim with water (without the rock in it), then put the rock in and measure the volume of the water that flowed out.
To find the volume of a piece of clay, you can use water displacement if the clay is irregularly shaped. Fill a graduated cylinder or a measuring cup with a known volume of water, then submerge the clay completely and measure the new water level. The volume of the clay is the difference between the initial and final water levels. Alternatively, if the clay is a regular shape, you can calculate the volume using the appropriate mathematical formula (e.g., for a cylinder, use V = πr²h).
This would be called a graduated cillender. But the ccs vary in this tool...from 100 to 1000 * * * * * A graduated CYLINDER might be a better choice!
Half fill a graduated glass beaker with water and note the level. Place irregularly shaped object into the beaker. Note the new level. The difference between the two levels is the volume of the object. cw: OK, that method works for objects that don't get wet -- like steel. Tissue paper would not be a good candidate. Also, if the object floats, you have to submerge the object.
It would be hard to find a line of symmetry on a moon, as it is likely to be irregularly shaped.
When you are trying to find the volume of an irregularly shaped object.
Immerse the object completely in a liquid (e.g. water) and measure the volume of liquid displaced.
You can find the volume of an irregularly shaped object, like a rock, by using the water displacement method. Submerge the object in a known volume of water in a container. Measure the increase in water level, which equals the volume of the rock.
A beaker. Simply fill the beaker with a known quantity of liquid. Drop the object into the beaker, and measure the difference in the fluid levels.
To find the volume of an irregularly shaped object that would dissolve in water, you can use the water displacement method. Fill a known volume of water in a container, note the initial water level, then submerge the object in the water and measure the new water level. The difference in water levels is the volume of the object.
To calculate the density of an irregularly shaped object, you would typically use a scale to measure its mass and a graduated cylinder to measure its volume by displacement of water. The density can then be calculated by dividing the mass by the volume.
Unknown: Volume of chunk of copperKnown:density = 8.94g/cm3 (Wikipedia)mass of irregularly shaped chunk of copper = 1.5kg = 1500gEquation:density = mass/volumeSolution:volume = mass/density = 1500g/8.94g/cm3 = 167.8cm3 = 170cm3 (rounded to two significant figures)
To find the density of an irregularly shaped object like a rock, you can use the water displacement method. First, measure the volume of water displaced when the rock is submerged in a known volume of water. Then, divide the mass of the rock by the volume of water displaced to calculate the density.
To calculate the volume of an irregularly shaped object, a good idea would be to get a bucket full of water and submerge that object into the bucket. Then measure the amount of water that runs over and that should be the volume of your object. For example if you take a sealed bottle of bottle stick it in a bucket filled with water, then let it's volume filll the space and displace the water. The water that is displaced or the water that runs out is the volume of your irregular shape. Get it?
One way would be to get a container into which you could put the rock completely, fill it to the brim with water (without the rock in it), then put the rock in and measure the volume of the water that flowed out.
To find the volume of a piece of clay, you can use water displacement if the clay is irregularly shaped. Fill a graduated cylinder or a measuring cup with a known volume of water, then submerge the clay completely and measure the new water level. The volume of the clay is the difference between the initial and final water levels. Alternatively, if the clay is a regular shape, you can calculate the volume using the appropriate mathematical formula (e.g., for a cylinder, use V = πr²h).
equal the density of any other piece, assuming that the original cube was made of the same uniform substance.