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A nickel is 5 cents and a quarter is 25 cents. If T is the total number of cents, the expression would be

T = 5n + 25y

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Q: How would you write an algebraic expression for the number of cents in n nickels and y quarters?
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Provided you have quarters and nickels together equaling 5.30 dollars in which there are 8 more quarters than nickels how many nickels and quarters are there?

19 Quarters & 11 Nickels Let X = number of quarters & Y = number of nickels So, X = Y +8 (8 more quarters than nickels) 0.25*X + 0.05*Y = 5.30 Substitute first equation for x into second equation: 0.25*(Y+8) + 0.05*Y = 5.30 0.25Y + 2 + 0.05Y = 5.30 0.30Y + 2 = 5.30 0.30Y = 3.3 Y = 11 nickels, so the number of quarters X = 19 We can check these values with the second equation: 0.25*19 + 0.05*11 4.75 + 0.55 = 5.30