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∙ 14y agoIts either 75 or 87 because I do not know if "sum" means the numbers added together (e.g 7+5) or if it is the actual number. 75 works for both, the actual number and them added together, 87 only works for them added together.
Wiki User
∙ 14y ago1
No. (Assuming a three digit number is in the range 100-999 and excludes leading zeros, that is 080 does not count as it is really 80 which is a two digit number) To be divisible by 11, the difference in the sums of the alternate digits of the number must be divisible by 11 (or 0). For a three digit number, this means that the sum of the first and last digits less the second digit must be a multiple of 11 (or 0). For a three digit number with all the digits the same, this calculation results in the value of one of the digits (eg 333 → 3 + 3 - 3 = 3) which will not be 0, and cannot be a multiple of 11 as a single digit is less than or equal to 9 which is less than 11 and thus not a multiple of 11.
5 (zeroes before the number don't count, zeroes after the number do)
5. Count the number of digits from the first non-zero digit to the last non-zero digit.
The first rule is to count all the digits from the beginning of the number until the first uncertain digit. The second rule is to round the final answer to match the least precise measurement used in the calculation.
1
The number is 949.
10,000....Count
it has 6 sig digits (405608) the 0.00 dont count
You would get the quotient first and count the digits.
A circle has no beginning.
No. (Assuming a three digit number is in the range 100-999 and excludes leading zeros, that is 080 does not count as it is really 80 which is a two digit number) To be divisible by 11, the difference in the sums of the alternate digits of the number must be divisible by 11 (or 0). For a three digit number, this means that the sum of the first and last digits less the second digit must be a multiple of 11 (or 0). For a three digit number with all the digits the same, this calculation results in the value of one of the digits (eg 333 → 3 + 3 - 3 = 3) which will not be 0, and cannot be a multiple of 11 as a single digit is less than or equal to 9 which is less than 11 and thus not a multiple of 11.
5 (zeroes before the number don't count, zeroes after the number do)
5. Count the number of digits from the first non-zero digit to the last non-zero digit.
Because this number does not have a decimal point, to count significant digits, we start at the right and start counting from the first non zero number. The first non zero number is 6 and this number has 4 significant digits.
The first rule is to count all the digits from the beginning of the number until the first uncertain digit. The second rule is to round the final answer to match the least precise measurement used in the calculation.
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }