Its either 75 or 87 because I do not know if "sum" means the numbers added together (e.g 7+5) or if it is the actual number. 75 works for both, the actual number and them added together, 87 only works for them added together.
1
To find the three-digit numbers divisible by 3 using the digits 0-9, we first note that a number is divisible by 3 if the sum of its digits is divisible by 3. The total number of three-digit combinations from the digits 0-9 can be calculated while ensuring that the first digit is not 0 (to maintain the three-digit property). Considering the digits 1-9 for the first digit (9 options) and 0-9 for the other two digits (10 options each), we can have (9 \times 10 \times 10 = 900) total combinations. However, determining the exact count of those that are divisible by 3 involves calculating the sum of the digits and checking divisibility, which requires more specific combinatorial analysis. Ultimately, a precise count would need either systematic counting or computational assistance.
No. (Assuming a three digit number is in the range 100-999 and excludes leading zeros, that is 080 does not count as it is really 80 which is a two digit number) To be divisible by 11, the difference in the sums of the alternate digits of the number must be divisible by 11 (or 0). For a three digit number, this means that the sum of the first and last digits less the second digit must be a multiple of 11 (or 0). For a three digit number with all the digits the same, this calculation results in the value of one of the digits (eg 333 → 3 + 3 - 3 = 3) which will not be 0, and cannot be a multiple of 11 as a single digit is less than or equal to 9 which is less than 11 and thus not a multiple of 11.
5 (zeroes before the number don't count, zeroes after the number do)
5. Count the number of digits from the first non-zero digit to the last non-zero digit.
1
To find the three-digit numbers divisible by 3 using the digits 0-9, we first note that a number is divisible by 3 if the sum of its digits is divisible by 3. The total number of three-digit combinations from the digits 0-9 can be calculated while ensuring that the first digit is not 0 (to maintain the three-digit property). Considering the digits 1-9 for the first digit (9 options) and 0-9 for the other two digits (10 options each), we can have (9 \times 10 \times 10 = 900) total combinations. However, determining the exact count of those that are divisible by 3 involves calculating the sum of the digits and checking divisibility, which requires more specific combinatorial analysis. Ultimately, a precise count would need either systematic counting or computational assistance.
The number is 949.
10,000....Count
When multiplying numbers with significant digits, count the total number of significant digits in each number being multiplied. The result should have the same number of significant digits as the number with the fewest significant digits. Round the final answer to that number of significant digits.
A circle has no beginning.
it has 6 sig digits (405608) the 0.00 dont count
You would get the quotient first and count the digits.
No. (Assuming a three digit number is in the range 100-999 and excludes leading zeros, that is 080 does not count as it is really 80 which is a two digit number) To be divisible by 11, the difference in the sums of the alternate digits of the number must be divisible by 11 (or 0). For a three digit number, this means that the sum of the first and last digits less the second digit must be a multiple of 11 (or 0). For a three digit number with all the digits the same, this calculation results in the value of one of the digits (eg 333 → 3 + 3 - 3 = 3) which will not be 0, and cannot be a multiple of 11 as a single digit is less than or equal to 9 which is less than 11 and thus not a multiple of 11.
5 (zeroes before the number don't count, zeroes after the number do)
5. Count the number of digits from the first non-zero digit to the last non-zero digit.
When multiplying numbers with significant digits, count the total number of significant digits in each number. Multiply the numbers as usual, but round the final answer to match the least number of significant digits in the original numbers.