(2x - 8)(-4x + 4) = -8x2 + 40x - 32
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
The diagonals will be equal and so: 4x-47 = 2x+31 => 4x-2x = 31+47 => 2x = 78 Therefore the value of x is: x = 78/2 => x = 39
y = 4x-8 and y = 2x+10 4x-8 = 2x+10 4x-2x = 10+8 2x = 18 x = 9 Substitute the value of x into the original equations to find the value of y: Therefore: x = 9 and y = 28
2x + 33 = 4x + 11 -11 -11 2x + 22 = 4x -2x -2x 22 = 4x Divide each side by 4 x = 5.5
(2x - 8)(-4x + 4) = -8x2 + 40x - 32
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
The diagonals will be equal and so: 4x-47 = 2x+31 => 4x-2x = 31+47 => 2x = 78 Therefore the value of x is: x = 78/2 => x = 39
y = 4x-8 and y = 2x+10 4x-8 = 2x+10 4x-2x = 10+8 2x = 18 x = 9 Substitute the value of x into the original equations to find the value of y: Therefore: x = 9 and y = 28
2x + 33 = 4x + 11 -11 -11 2x + 22 = 4x -2x -2x 22 = 4x Divide each side by 4 x = 5.5
Given .........................................4x+11-2x+13=32 Combine like terms ....................2x+24=32 Subtract 24 from both sides ......2x=8 Divide both sides by 2 ...............x=4
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
Find the value of 'x' when 2x+8=4x+20 First subtract '2x' from both sides. 8=2x+20 Then subtract '20' from each side. -12=2x Then divide each side by '2' -6=x. Therefore 'x=-6'
If 4x-2 equals 2x-34 then x is equal to -16. 4x is equal to 2x-322x is equal to -32x is therefore -16
4x - 2x = 2x
y = 5 - 2x so 4x + 6(5 - 2x) = -2 ie 4x + 30 - 12x = -2 Subtract 30 from each side: 4x - 12x = -32 ie -8x = -32 so x = 4 and y = -3
(The original question was misphrased.) 4x-7 = 2x+5 resolves as 2x-7 = 5 2x = 12 x = 6