If 3x - 1 = 11: To solve this equation, add 1 to each side of the equation to isolate x (3x -1 +1 = 11 + 1) and now the equation is 3x = 12. The next step is to divide both sides of the equation by 3 to find the value of x (3x / 3 = 12 / 3) for the answer x = 4. Not sure what you mean by x2 x, but you can substitute the value of x (which is 4) to solve.
- If 3X - 1 = 11, what is the value of X^2 + X?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
The vertex has a minimum value of (-4, -11)
11
x=-11
- If 3X - 1 = 11, what is the value of X^2 + X?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
The vertex has a minimum value of (-4, -11)
11
Given the limited information in the question, Z is maximised when x1 or x2 (or both) are maximised. There is no trade-off between x1 and x2 to worry about.
3x-1=11 solves to x=4. Plug in 4 to get 42+4. The answer is 20.
13
if x2 = 5 the value of x has to be 5 divided by 2 which is 2.5 x = 2.5
11-x2=-5 add -11 to both sides: 11-x2-11=-5-11 -x2=-16 divide both sides by -2: (-x2)/(-2)=(-16)/(-2) x=8 If the "x2" was supposed to be "x2", meaning exponentiation, ("x squared") and not "x2", implying multiplication, ("x times two") then we'd get: x2=16 x=±4
If x = 8 then x2 = 82 = 8 x 8 = 64