Assuming the equation given is 3x - 6 = 30, solve for x by isolating the known from the unknown and dividing by the number of x's: 3x - 6 = 30 (isolate the known from unknown by adding 6 to each side) 3x = 36 (now divide both sides by the nuber of x's [3] to solve for x) x = 12
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3x + 6 = 30 Therefore, 3x = 24 x = 24/3 x = 8
3x-6y=30 y=34-6x substitute the the value for y from the second equation into the first equation. 3x-6(34-6x)=30 3x-204+36x=30 39x-204=30 39x=234 x=234/39 x=6 Substitute this value of x into equation 2. y=34-6(6) y=34-36 y=-2
If: 3x+20 = 2x-10 Then: x = -30
Either move the negative over to the other side to become positive, or divide the entire equation by -1 to get it to a positive. Example: -3x + 12 = 30 Move the -3x over to get 12 = 30 + 3x 12 - 30 = 3x - 18 = 3x - 6 = x OR Divide by -1 to get 3x - 12 = - 30 3x = - 30 + 12 3x = -18 x = -6
when a problem looks like this: for example: 6(5+3x) 6 x 5 = 30 and 6 x 3x = 18x so it would be 30 + 18x