If 9 counters represent the whole set, to find five-thirds of the set, you multiply 9 by ( \frac{5}{3} ). This calculation gives you ( 9 \times \frac{5}{3} = 15 ). Therefore, there are 15 counters in five-thirds of the set.
9
35 x 2 = 70There are 70 counters in a whole set.
To find the total number of counters in the whole set, you can set up a proportion. If 75 counters represent 34 of the set, you can write it as ( \frac{75}{34} = \frac{x}{100} ), where ( x ) is the total number of counters in the whole set. Solving for ( x ) gives ( x = \frac{75 \times 100}{34} ), which calculates to approximately 220.59. Since you can't have a fraction of a counter, you would round to 221 counters in the whole set.
24 counters = 8/824 * 5/8 = 15
If 15 counters are the whole set, how many are 3/5 of the set 5
9
Assuming counters = C. 12C = 3/4set. 48C = 3set. 16 = 1 Set.
two
35 x 2 = 70There are 70 counters in a whole set.
24 counters = 8/824 * 5/8 = 15
To find the total number of counters in the whole set, you can set up a proportion. If 75 counters represent 34 of the set, you can write it as ( \frac{75}{34} = \frac{x}{100} ), where ( x ) is the total number of counters in the whole set. Solving for ( x ) gives ( x = \frac{75 \times 100}{34} ), which calculates to approximately 220.59. Since you can't have a fraction of a counter, you would round to 221 counters in the whole set.
If 15 counters are the whole set, how many are 3/5 of the set 5
16 is the whole set
16 counters is 4/5 of all 20 counters.16/20
3/5 * 15 = 9
2/3
16