If its a right triangle, use SoH CaH Toah, or Sine = opposite over hypotenuse, Cosine = adjacent over hypotenuse, and tangent = opposite over the adjacent. So, to solve your problem, if "c" is the right angle, Tan(a) = bc/ca or Tan(30)=5/ca or .577 = 5/ca or (.577)*ca = 5 or ca=5/(.577) or ca= 8.66
No, because 5 over 1 equals 5 and 1 over 5 equals 5 but 5 over 5 equals 1
41 degrees Fahrenheit equals 5 degrees Celsius.
x = 74.05 degrees, approx
C = ( F - 32 ) * 5 / 9whereC is degrees Celsius or CentigradeF is degrees FahrenheitC = (41 - 32 ) * 5 / 9 = 541 degrees Fahrenheit is 5 degrees Celsius
SOHCAHTOAA way of remembering how to compute the sine, cosine, and tangent of an angle.SOH stands for Sine equals Opposite over Hypotenuse.CAH stands for Cosine equals Adjacent over Hypotenuse.TOA stands for Tangent equals Opposite over Adjacent. Example: Find the values of sin θ,cos θ, and tan θ in the right triangle 3, 4, 5. Answer:sin θ = 3/5 = 0.6cosθ = 4/5 = 0.8tanθ = 3/4 = 0.75
If its a right triangle, use SoH CaH Toah, or Sine = opposite over hypotenuse, Cosine = adjacent over hypotenuse, and tangent = opposite over the adjacent. So, to solve your problem, if "c" is the right angle, Tan(a) = bc/ca or Tan(30)=5/ca or .577 = 5/ca or (.577)*ca = 5 or ca=5/(.577) or ca= 8.66
No, because 5 over 1 equals 5 and 1 over 5 equals 5 but 5 over 5 equals 1
You plug in the (degrees F), do the arithmetic, and wind up with the (degrees C).
41 degrees Fahrenheit equals 5 degrees Celsius.
1 and 2/5
Minus 5 degrees Celsius is equal to 23 degrees Fahrenheit.
One degree of latitude (north or south) equals 60 nautical miles. One degree of longitude (east-west) is approximately 60 nautical miles times the cosine of the mid-latitude. So 5 degrees is something less than 300 NM, depending on the heading and the latitude.
23 degrees Fahrenheit = -5 degrees Celsius.
-15 degrees Fahrenheit -15 degrees Celsius
x = tan-1(5) = 78.69 degrees
5 deg C = 41 deg F