distance=rate*time
Jill can paint 1 house in 5 hours. 1=r*5 r=1/5 houses/hour
Tom can paint 1 house in 4 hours. 1=r*4 r=1/4 houses/hour
1 house = 1/5*x+1/4*x
1=(4x+5x)/20
20=9x
x= 2.2 repeating hours (2 hours, 13 minutes, 20 seconds)
144 minutes.
2.25 hrs
It would take them 4 hours to paint the house together.
Delbert can paint the fence in 11 hours so in 1 hour Delbert paints 1/11 of a fence. Similarly, in 1 hour Dorothy paints 1/12 of a fence. So together, in 1 hour they paint 1/11 + 1/12 = 12/132 + 11/132 = 23/132 of a fence. So to paint the fence together they would need 1 / (23/132) = 132/23 hours = 5.74 hours
Assuming that there is no synergy, nor time wasted when the two of them start chatting, M paints 0.2 rooms per hour F paints 0.166.. rooms per hour so M + F paint 0.366... rooms per hour So it takes them 1/0.366... = 2.7272... hours
In one hour Sally paints one quarter and John paints one sixth, between them they paint five twelfths per hour so would take 2 hours 24 minutes if they worked together. But have you ever known a male and a female to work harmoniously together? Allow at least three hours!
144 minutes.
2.25 hrs
It would take them 4 hours to paint the house together.
Joe can paint the house in 3 hours so Joe paints 1/3 house in an hour. Similarly, Sam paint 1/5 of the house in one hour. So together (assuming no synergy) they paint 1/3 + 1/5 = 8/15 of the house in an hour. So they take 15/8 = 1 + 7/8 = 1.875 days to paint it.
if sally can paint a house in 4 hours and john can paint the same house in 6 hours, how long will it take for them to paint the house together?
Delbert can paint the fence in 11 hours so in 1 hour Delbert paints 1/11 of a fence. Similarly, in 1 hour Dorothy paints 1/12 of a fence. So together, in 1 hour they paint 1/11 + 1/12 = 12/132 + 11/132 = 23/132 of a fence. So to paint the fence together they would need 1 / (23/132) = 132/23 hours = 5.74 hours
s ofoil paint together
I work for Sherwin Williams paints and from what I understand it is our paints that paint The White House. The paint is a special mix. Everyone who comes in contact with the paint has to go through a background check.
Assuming that there is no synergy, nor time wasted when the two of them start chatting, M paints 0.2 rooms per hour F paints 0.166.. rooms per hour so M + F paint 0.366... rooms per hour So it takes them 1/0.366... = 2.7272... hours
We know that Sally can paint the house by herself in four hours. Put another way, she can paint 1/4 of the house in an hour. Using similar logic, we know John paints at a rate of just 1/6 of a house per hour. If we convert those fractions to fractions with a common denominator, we have 3/12 of a house for Sally and 2/12 of a house for John, so together they can paint at a rate of 5/12 of a house per hour. But that is not yet the answer to the question. If you take the reciprocal of 5/12 houses per hour, you get 12/5 hours per house. That equals 2.4 hours per house. Converting to hours and minutes, you get 2 hours, 24 minutes -- because 0.4 hours equals 24 minutes. (0.4 hours x 60 minutes/hour = 24 minutes.) Algebra OR Above answer of this question is right.but we can also define it some other way, in percentage. May be this solution make esay for some friends to understand.Silly tooks 4 hors to paint 100 % (full house).Jhon tooks 6 hours to paint 100 % (Full house).In an hoursilly can paint 25 % of house & Jhon can paint 16.66 % of house, so they both can paint 41.66 percent of house in an hour.so, if we divide (total required work) / (work they can do in an Hour)= 100 / 41.66we I'll get the total time to paint complete house.ANSWERS IS : 2.4 Hours or 2 hours 24 minutes.
Red and black