If you move at a rate of 29 mm per year, in 10,000 years, you would travel a distance of 290,000 mm. To convert this into meters, you divide by 1,000, resulting in 290 meters. Therefore, at that rate, you would cover 290 meters over the span of 10,000 years.
$14,693.28
To calculate the amount John will have after two years with a principal of $10,000 invested at an annual compound interest rate of 10%, we can use the formula for compound interest: [ A = P(1 + r)^n ] where ( A ) is the amount after time ( n ), ( P ) is the principal, ( r ) is the interest rate, and ( n ) is the number of years. Plugging in the values, we get: [ A = 10000(1 + 0.10)^2 = 10000(1.10)^2 = 10000(1.21) = 12100. ] Thus, after two years, John will have $12,100.
% rate:= 170000/10000 * 100%= 17 * 100%= 1700%
% rate = 0.19% = 19/10000 * 100% = 19/100 * 1% = 0.19%
3000
$14,693.28
$7,903.50 if the intrest rate is 4% (A high bank intrest rate percentage)
% rate:= 170000/10000 * 100%= 17 * 100%= 1700%
126
Sed rate is a type of measure of infection in the blood. Sed rate of 17 is within the normal range for both men and women. The normal rate for women is 0-29mm/hr. and the normal rate for men is 0-22 mm/hr.
Interest = Principal x rate x time 17000= 100000(0.10) t 17000=10000 t t=17000/10000 t=1.7 years
% rate:= 10000/200000 * 100%= 0.05 * 100%= 5%
6%
% rate:= 10000/20000000 * 100%= 0.0005 * 100%= 0.05%
% rate = 0.06667% = 10000/1500000000 * 100% = 0.0006667 * 1% = 0.06667%
% rate = 0.19% = 19/10000 * 100% = 19/100 * 1% = 0.19%
3000