if the bases are b1 and b2, then: area = ½ × (b1 + b2) × h → 2 × area ÷ h = b1 + b2 → b2 = 2 × area ÷ h - b1 = 2 × 156.6 m² ÷ 18 m - 6 m = 11.4 m
t1 s1 b1 t1 s1 b2 t1 s2 b1 t1 s2 b2 t2 s1 b1 t2 s1 b2 t2 s2 b1 t2 s2 b2 t3 s1 b1 t3 s1 b2 t3 s2 b1 t3 s2 b2 TOTAL 12 combinations OR 2(3 x 2) = 12
A=1/2(b1+b2)h A=1/2(7+12)5 A=1/2(19)5 A=9.5x5 A=47.5
In Excel, B1 is a cell address where column B and row 1 meet.
V= 1/2 (b1+b2) x h x L Volume = (area of the cross section) x (the length L) V = [ 1/2 (base1 +base 2) x height ] x length
if the bases are b1 and b2, then: area = ½ × (b1 + b2) × h → 2 × area ÷ h = b1 + b2 → b2 = 2 × area ÷ h - b1 = 2 × 156.6 m² ÷ 18 m - 6 m = 11.4 m
the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2
t1 s1 b1 t1 s1 b2 t1 s2 b1 t1 s2 b2 t2 s1 b1 t2 s1 b2 t2 s2 b1 t2 s2 b2 t3 s1 b1 t3 s1 b2 t3 s2 b1 t3 s2 b2 TOTAL 12 combinations OR 2(3 x 2) = 12
Area = a [(b1 + b2)/2]a = altitude (height) of the trapezoidb1 = length of one baseb2 = length of the other base
Answer: No.Explanation: Area of trapezoid = 1/2(b1 + b2) * h where b1 is length of base one, b2 is length of base 2 and h is height.this equation = 1/2*b1*h + 1/2*b2*hdouble one base:1/2(2*b1+b2) *h = b1*h+1/2*b2*h = (b1+1/2*b2)*hin order for the area to double, both bases would have to double which would cancel out both 1/2's. Only one is cancelled out so the area would increase but not double
Their are actually a few different types of blood a human can have. These are the different types: - A - B - AB - O Information Source:http://en.wikipedia.org/wiki/ABO_blood_group_system
B1 in science is you and genes
"=((B1-A1)/B1)*100" alternatively if you format the cell as a %, it would just be "=(b1-a1)/b1"
The easy way to answer this is to plug in numbers. Because you are given "12" and you are given "twice as many", the answer has to be a variable of 12 or 6. If you start plugging in numbers, you will find that 36 is the answer... Ben and Jerry start with 36 cards. Ben gives 12 of his cards to Jerry. Ben now has 24 and Jerry now has 48. 24 is one half of 48. For the actual math, you have to use variables. Please stick with it, this gets a little ugly if the child you are working with is as young as mine is. Ben at the start is equal to B0 Jerry at the start is equal to J0 At the start B0=J0 Now, Ben gives 12 of his cards to Jerry. The new value for Ben is B1 and B1 = B0-12. The new value for Jerry is J1 and J1 = J0+12. Also, we know that the new Jerry is twice the amount of the new Ben...J1 =B1 x 2. So, the below are known: 1: B0=J0 2: B1 = B0-12 3: J1 = J0+12 4: J1 = B1 x 2 So, using the last known, start to substitute the other values to get everything equal to the same variable. In this case, I'm going to solve it for B0. J1 = B1 x 2 J1 = (B0-12)x2 - Substitute B1 for B0-12, see line 2 J0+12=(B0-12)x2 - Substitute J1 for J0+12, see line 3 B0+12=(B0-12)x2 - Substitute J0 for B0, see line 1 1/2B0+6 = B0-12 - Divide the whole equation by 2 +6=B0-12-1/2B0 - Subtract 1/2B0 from both sides +18=B0-1/2B0 - Add 12 to both sides +18=1/2B0 - Simplify equation 36=B0 - Multiply both sides by 2 There is probably an easier way to do the above, but that's how I worked it out on paper.
The area of a trapezoid is one-half the product of the length of an altitude and the sum of the lengths of the bases: A=1/2(b1 + b2)
B1 is a relative reference.
You could use either of the following, by putting the formulas in any cells except A1 and B1: =A1+B1 =SUM(A1:B1)