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What figure is the locus of all points that are equidistant from two fixed points?
A line in 2D and a plane in 3D A perpendicular bisector of the line connecting the 2 given points
Which geometric object is defined as the set of all points in a Plane that are equidistant from 2 points?
The geometric object defined as the set of all points in a plane that are equidistant from two points is called the perpendicular bisector. This line is perpendicular to the segment joining the two points and bisects it, meaning it divides the segment into two equal parts. Any point on this line has the same distance to both of the original points.
What is equidistant from the two end points of a line segment?
the middle point * * * * * In 2 dimensions: also any point on line forming the perpendicular bisector of the line segment. In 3 dimensions: the plane formed by the perpendicular bisector being rotated along the axis of the line segment. In higher dimensions: Hyperplanes being rotated along the same axis.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
What is the locus of points in a plane that are equidistant from points A and B in the plane?
a straight line ..
If R and S are two points in the plane the perpendicular bisector of RS is the set of all points equidistant from R and S?
True
If p and Q are two points in the plane. the perpendicular bisector of pq is the set of all points equidistant from p and q?
True
What figure is the locus of all points that are equidistant from two fixed points?
A line in 2D and a plane in 3D A perpendicular bisector of the line connecting the 2 given points
Is it true or false If R And S Are Two Points In The Plane The Perpendicular Bisector Of RS Is The Set Of All Points Equidistant From R And S?
True
What is the locus of points in a plane equidistant from the sides of an angle?
A line that is the angle bisector.
Which geometric object is defined as the set of all points in a plane that are equidistant from the two sides of a given angle?
Bisector of an angle, is defined as the set of all points in a plane that are equidistant from the two sides of a given angle.
Which of the following best describes a bisector of an angle?
The set of all points in a plane that are equidistant from the two sides of a given angle
Which geometric object is defind as the set of all points in a plane that are equidistant from the two sides of a given angle?
angle bisector
What is equidistant from the two end points of a line segment?
the middle point * * * * * In 2 dimensions: also any point on line forming the perpendicular bisector of the line segment. In 3 dimensions: the plane formed by the perpendicular bisector being rotated along the axis of the line segment. In higher dimensions: Hyperplanes being rotated along the same axis.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
What is the set of all points in the plane equidistant from one point in the plane?
The set of all points in the plane equidistant from one point in the plane is named a parabola.
What is the perpendicular bisector equation of the line with end points of -1 4 and 3 8 on the Cartesian plane?
Points: (-1, 4) and (3, 8) Midpoint (1, 6) Slope: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7
