4*pi = 12.6 cubic feet.
261.66
Answer: the barrel will hold 9.42 ft³ of water.
Do you mean a cylinder with a diameter of 5 feet and length of 12 feet? This would hold about 235.6 cubic feet or 1762.5 gallons
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
If the sides are straight ... the diameter is 3-ft all the way down ... andthe bottom is flat, then the water is a cylinder.Volume of a cylinder = pi R2 H = pi (1.5)2 (3) = 21.206 cubic feet = 158.6 gallons (rounded)
261.66
A cylinder 50 feet in height and 6 inches in diameter can hold up to 73.44 gallons of water.
Answer: the barrel will hold 9.42 ft³ of water.
Do you mean a cylinder with a diameter of 5 feet and length of 12 feet? This would hold about 235.6 cubic feet or 1762.5 gallons
To calculate the volume of water a water main will hold, we can use the formula for the volume of a cylinder: V = πr²h. First, convert the diameter to radius (18 inches diameter means a radius of 9 inches or 0.75 feet). The length of the water main is 2 miles, which is 10,560 feet. Plugging these values into the formula, we find the volume is approximately 43,500 cubic feet, which is about 326,000 gallons of water.
5.456 cu.ft
8.8 gallons of water.
Filled to the top, this well would hold about 956 gallons of water.
The volume is 31.809 cubic feet.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
If the sides are straight ... the diameter is 3-ft all the way down ... andthe bottom is flat, then the water is a cylinder.Volume of a cylinder = pi R2 H = pi (1.5)2 (3) = 21.206 cubic feet = 158.6 gallons (rounded)