Wiki User
∙ 13y ago7000/60=116.66667 m/s
Wiki User
∙ 13y agoNo. If you can drive around a ten-mile track in the same time it takes you to drive around a one-mile track, then your angular velocity is the same in both cases. But in order to do that, you'll need much higher tangential velocity during the longer run. Tangential velocity is what you'd normally call your 'speed' as you blaze around the track.
sure.
The closing velocity is speed1 plus speed2, so the trains are moving toward each other at 250 mph. 2000/250 = 8. The trains will meet in 8 hours.
No. Acceleration is the change in velocity(speed) over a period time.=====================================Another contributor bristled:Sorry. Velocity and speed are not two different words for the same thing.Velocity means speed and direction, and acceleration means any change in velocity.If the speed is constant but the direction is changing ... like turning a corner or drivingon a circular track ... then velocity is changing, and there is acceleration.
His velocity was zero - since he's back to where he started. (Try to substitute speed where appropriate.)
Yes, if you run around a track at a constant speed of 5 km/h, your velocity is constant because velocity includes both speed and direction. As long as you maintain this speed and direction, your velocity remains constant.
Cart experiences a change in velocity(which is a vector quantity, not like speed). Cart's velocity on circular track has to be tangent to track at each point and because of that it has to change its direction. Speed may or not remain the same, you can't tell it changes in each possible case. Mass and weight remain the same.
No. If you can drive around a ten-mile track in the same time it takes you to drive around a one-mile track, then your angular velocity is the same in both cases. But in order to do that, you'll need much higher tangential velocity during the longer run. Tangential velocity is what you'd normally call your 'speed' as you blaze around the track.
no
sure.
What is the math formula which would solve this question?
The average velocity of a runner who completes one lap of a 400m track in 75 seconds is 5.33 m/s. This is calculated by dividing the distance traveled (400m) by the time taken (75s).
The closing velocity is speed1 plus speed2, so the trains are moving toward each other at 250 mph. 2000/250 = 8. The trains will meet in 8 hours.
One example of Velocity is that if you are running in the same direction, your speed and velocity is the same. But if you are running AROUND the track, your speed is the same but your velocity is changing.
Even though the person is moving at a constant speed, they are changing direction constantly as they go around the track. Since acceleration is defined as any change in velocity, and velocity includes both speed and direction, the person running on a circular track is experiencing acceleration.
While the speed may be constant, the velocity changes because velocity is a vector quantity that includes direction. As the car drives around the circular track, its direction constantly changes, causing the velocity to change even though the speed remains the same. This change in velocity is due to the centripetal acceleration required to keep the car moving in a circular path.
No, the average velocity is not zero. Average velocity is the total displacement divided by the total time taken. For one lap around the track, the athlete ends up back at the starting line, so the total displacement is not zero.