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∙ 15y agoThe combined gas law say PV/T=k. 1.3*18/300=k=V*24/340 V=1.3*18*340/(300*24)=11.05 litres
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∙ 15y ago1 mole of gas at STP occupies 22.4 liters.
13500 litres of water weights approx 132.3 newtons.
meters, seconds, meters/second, liters, newtons
Density = 10 kg / 5 litres = 2 kg per litre.
If the volume is reduced, and all else remains the same, then the pressure will increase by a factor of 2, or it will double.
0.50 moles of NH3 at STP (Standard Temperature and Pressure) occupies 11.2 liters of volume.
One mole of any gas at STP occupies 22.4 liters. Therefore, one mole of oxygen gas at STP also occupies 22.4 liters.
This is the molar volume of an ideal gas at a given temperature and pressure.
The volume of 0.8 moles of a gas at Standard Temperature and Pressure (STP) is 17.6 liters. This is because at STP, one mole of any ideal gas occupies 22.4 liters.
5.3 liters
The answer is 1,83 moles.
You divide the liters of gas by 22.4 to convert to moles. This is because one mole of gas at standard temperature and pressure (STP) occupies 22.4 liters.
1 mole of gas at STP occupies 22.4 liters.
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
At room temperature and pressure, 1 mole of ideal gas occupies 22.4 liters. Therefore, 8.00 moles of oxygen will occupy 8.00 x 22.4 = 179.2 liters.
The volume of one mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters.