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There are a couple of ways to look at this problem, so the wording is very important. The question you ask is the distance actually traveled, which is measured along the outside of the circle. Because the circle turns 100 degrees, or 100/360 of a full rotation, and the circumference is 4*pi, this distance is

(100/360)*(4*pi) = 3.49 inches (approx)

You can also ask what the displacement of the point is, which is the straight-line distance from its starting point to the ending point and is measured along the chord drawn between the points. This distance is the base of an isosceles triangle with equal sides of length 2 inches and an angle of 100 degrees between them. One way to calculate that length is to apply the law of sines (and note that the remaining two interior angles have measure 40 degrees):

base = (2 / sin 40) * sin 100 = 3.06 inches (approx)

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Q: If a circle with a diameter of 4 inches rotates 100 degrees what distance will any one spot on its edge actually travel?
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