Correct.
NO it is not because if a<b<c it could also be said without the b as a<c.
Absolutely not
b+b+b+c+c+c+c =3b+4c
a is 6 less than d.
If two positive fractions are less than 1, it means that both fractions can be expressed as ( a/b ) and ( c/d ), where ( a < b ) and ( c < d ). When you multiply these fractions, the product is ( (a/b) \times (c/d) = (a \times c) / (b \times d) ). Since both ( a ) and ( c ) are less than their respective denominators ( b ) and ( d ), the numerator ( a \times c ) will also be less than the denominator ( b \times d ). Thus, the product remains a positive fraction less than 1.
A plus b plus c equals d. A is the largest answer b is the smallest answer and d is less than 6?''
I believe that's usually treated as an axiom, meaning you don't prove it.
You already said the answer that b is less than c
a < b < c So, neither a nor b is greater than c.
NO it is not because if a<b<c it could also be said without the b as a<c.
Absolutely not
False. A is greater than C. ******************** I'm not in calculus but if A isn't less than B, then that means its either greater than or equal to it. and if B isn't less than C then its greater or equal to. so that means that A is either greater than or equal to C. so that means that A than C.
b+b+b+c+c+c+c =3b+4c
A is greater than B (A>B). C is less than D (C<D). But what about "less than or equal"?
b + b + b + c + c + c + c = 3b + 4c
4
a is 6 less than d.