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Yes, a multiple is "a number that can be divided by another number without a remainder".
If the number is a multiple of 4 or 8 then it is divisible by 4 and 8 with no remainder If a number can be halved and the answer is even, it was divisible by 4.If the number can be halved twice and the answer is stilleven, it was divisble by 8.
Multiples of 8 are also multiples of 4 because 8 is a multiple 4. In any number that is a multiple of 8, there are always two times the amount of 4's as 8's because 4 is half of 8. For example, the number 24 has three 8's adding up to become that number or it has six 4's that add up to that number.
8 is a multiple and is not a perfect square.
Number which is a factor of 8 butnot a multiple of 4 = 1factors of 8 = 1, 2, 4, 8multiples of 4 = 4, 8, 12, 16, 20, 24, 28,...
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The Least common multiple of 4 and 8 is 8.Since 8 is a multiple of 4, it is automatically the LCM.8it is the smallest common multiple between the two, despite also being the value of one of the two numbers.
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A multiple of any number would be the product of that number and any other nonzero whole number. A multiple of 4 is 8. A multiple of 100 is 300.
What numbers are between 61 and 107 are multiples of 4, 5 and 8
A number that ends in 3 can't be a multiple of 4 because the 4 times table goes in a pattern, (e.g 4, 8, 12, 16, 20, 24.) If the number ends in either 0 2 4 6 8 then it couldbe a possible multiple of 4. It always ends in an even number. 3 is not an even number so it is not going to be the last number of a multiple of 4.
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They can go into 8*4*9 = 288. That is not the smallest such number, but that was not the question.
No. Since 4 is an even number, then any multiple of 4 will also be an even number. An even number will have an even digit in its ones place (0,2,4,6, or 8).
4- last two digits are a multiple of 4 7-take the last digit and subtract it from the rest of the number and if multiple of 7 (including 0) 8- last three digits are multiple of 8