A multiple of 11
There is not one. A prime number has exactly two factors, 1 and itself. The only way that a prime number could be divisible by 48 is if 48 were a prime number, which it is not.
293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
yes EDIT: not always ! Only if the number is even - for example 120, 160, 220, 380 etc is it divisible by both 10 and 20. The numbers 30, 90, 150 350 etc cannot be exactly divided by 20 EDIT: Sorry for that. 30,90,150, 350 are even. I meant numbers with a odd digit in them.
No number is ever divisible by zero.
Yes, but it is a prime number and is divisible only by 1 and itself.
It is a number only divisible by one and itself.
Two is a prime number so it is only evenly divisible by one and itself.
yes it can only be an even number
There is not one. A prime number has exactly two factors, 1 and itself. The only way that a prime number could be divisible by 48 is if 48 were a prime number, which it is not.
293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.
Short answer: 2 The only number by which a factor of 4 may always be divided (other than 4) is 2.
yes EDIT: not always ! Only if the number is even - for example 120, 160, 220, 380 etc is it divisible by both 10 and 20. The numbers 30, 90, 150 350 etc cannot be exactly divided by 20 EDIT: Sorry for that. 30,90,150, 350 are even. I meant numbers with a odd digit in them.
There is always a GCF, even if it's only 1.
No - numbers are only divisible exactly by ten - if they end in a zero !
No number is ever divisible by zero.
There is no number, no matter the number of digits, that is only divisible by 2.
78 is not prime. No even number (except 2) is prime. Remember the definition. A prime number is exactly divisible only by itself and 1.