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This problem is an algebra-based problem using applications of oscillations. The rod is a length L with the axis of rotation in the center.

I found the answer to be that T = PIE x Sq root of (2L(m1 + m2) / (m1 - m2)g)

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Q: If a physical pendulum consists of light rod length suspended in the middle A large mass is attached to one end of the rod and a lighter mass is attached to other end what is T of oscill of pendulum?
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In a simple pendulum, with its entire mass concentrated at the end of a string, the period depends on the distance of the mass from the pivot point. A physical pendulum's period is affected by the distance of the centre-of-gravity of the pendulum arm to the pivot point, its mass and its moment of inertia about the pivot point. In real life the pendulum period can also be affected by air resistance, temperature changes etc.


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