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If a racing car's speed is 96 ms in 1 s what is the racing car's acceleration?
Wiki User
∙ 14y ago
Assuming the car begins at rest (0 m/s), and it has to reach 96 m/s in 1s, then, by the suvat equations:
s = - (displacement)
u = 0 ms-1 (initial velocity)
v = 96 ms-1 (final velocity)
a = ? (acceleration)
t = 1s (time)
a = (v-u)/t
a = (96-0)/1 ms-2
a = 96 ms-2
Wiki User
∙ 14y ago
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What is the cars speed in miles per hour when the speedometer reads 96 kilometers per hour?
96 km/hr = 59.7 mph (rounded)
What is the acceleration of a car that goes from 32 miles per second to 96 miles per second in 8 seconds?
Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------
Find the uniform acceleration that causes a cars velocity to increase from 32 ms to 96 ms in a period of 8 seconds?
Try 8 m/s^2 After one second, it would have increased velocity by 8 ms, making it 40 ms After two seconds, it would be 48 ms After 3, 56 4, 64 5, 72 6, 80 7, 88 8, 96 Calculation to find this- 96-32= 64, which will be evenly divided by 8 if it is a uniform acceleration, so 64/8= 8, accelerations units are meters per second squared, so 8 m/s^2
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What is the acceleration of a car that goes from 32 meters per second to 96 meters per second in 8 seconds?
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What is the the uniform acceleration that causes a car velocity to increase from 32 ms to 96 ms in a period of 8.0 seconds?
The average acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time taken. Plugging in the values, we get: (96 m/s - 32 m/s) / 8 s = 8 m/s^2. Therefore, the uniform acceleration that causes the car's velocity to increase from 32 m/s to 96 m/s in 8.0 seconds is 8 m/s^2.
