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Assuming the car begins at rest (0 m/s), and it has to reach 96 m/s in 1s, then, by the suvat equations:

s = - (displacement)

u = 0 ms-1 (initial velocity)

v = 96 ms-1 (final velocity)

a = ? (acceleration)

t = 1s (time)

a = (v-u)/t

a = (96-0)/1 ms-2

a = 96 ms-2

Q: If a racing car's speed is 96 ms in 1 s what is the racing car's acceleration?

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96 km/hr = 59.7 mph (rounded)

Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------

Try 8 m/s^2 After one second, it would have increased velocity by 8 ms, making it 40 ms After two seconds, it would be 48 ms After 3, 56 4, 64 5, 72 6, 80 7, 88 8, 96 Calculation to find this- 96-32= 64, which will be evenly divided by 8 if it is a uniform acceleration, so 64/8= 8, accelerations units are meters per second squared, so 8 m/s^2

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Acceleration = (change in speed) divided by (time for the change)Acceleration = (96 - 32) / 8 = 64/8 = 8 meters per second2

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96 km/hr = 59.7 mph (rounded)

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The net force needed can be calculated using Newton's second law, which states that force equals mass times acceleration. Therefore, the net force required to give a 40.0 kg grocery cart an acceleration of 2.4 m/s^2 is 96 N (40.0 kg x 2.4 m/s^2).

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The average acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time taken. Plugging in the values, we get: (96 m/s - 32 m/s) / 8 s = 8 m/s^2. Therefore, the uniform acceleration that causes the car's velocity to increase from 32 m/s to 96 m/s in 8.0 seconds is 8 m/s^2.