(1) L = 7W + 3
(2) 2L + 2W = 54
Substituting (1) in (2) ...
2(7W+3) + 2W = 54
14W + 6 + 2W = 54
16W = 48
W = 3
L = 7x3 + 3 = 24
So, length is 24 and width is 3
No, two rectangles with the same perimeter do not necessarily have the same area. The area of a rectangle is calculated as length multiplied by width, while the perimeter is the sum of all sides. For example, a rectangle with dimensions 2x5 (perimeter 14) has an area of 10, while a rectangle with dimensions 3x4 (also perimeter 14) has an area of 12. Thus, rectangles can have the same perimeter but different areas.
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.
No, not all rectangles have even perimeters. The perimeter of a rectangle is calculated using the formula ( P = 2(length + width) ). If either the length or width is an odd number, their sum can be odd, resulting in an odd perimeter when multiplied by 2. Therefore, a rectangle can have an odd perimeter if one or both dimensions are odd.
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
No rectangle can have equal perimeter and length.
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.
No, not all rectangles have even perimeters. The perimeter of a rectangle is calculated using the formula ( P = 2(length + width) ). If either the length or width is an odd number, their sum can be odd, resulting in an odd perimeter when multiplied by 2. Therefore, a rectangle can have an odd perimeter if one or both dimensions are odd.
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
Length = 9 Width = 9 Your rectangle is a square.
If the given dimensions are the length and width of a rectangle then its perimeter is 15.6+4.5+15.6+4.5 = 40.2
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
It is: 2(x+y) = perimeter whereas x is the width and y is the length of the rectangle
The dimensions of a rectangle are the length and the width. With these two measurements , the area of the rectangle can be calculated : Area = length x width. The perimeter can also be found : Perimeter = (2 x length) + (2 x width).