Wiki User
∙ 14y agoThe gravitational acceleration would be the change in velocity divide by the time required. For this example 8.15 m/sec divided by 5 seconds yields 1.63 m/s2.
(The actual average lunar gravity is estimated at 1.622 m/sec2.)
Wiki User
∙ 14y agoAssuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
On Earth, that is about 980.
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
10000 m/s2.
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
On Earth, that is about 980.
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
If an object is dropped near the surface of a planet, then the distance it fallsduring the first ' S ' seconds after it's dropped is(1/2) (acceleration of gravity on that planet) (S2) .The object's mass doesn't matter, because it makes no difference.
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
There are 3.28 feet in a meter.The accepted value for Gravitational on earch is 9.8 m/s2convert to feet = 32.2 ft/s2
10000 m/s2.
The acceleration of the stone when it is dropped from the top of a tower is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 downward. This acceleration remains constant as the stone falls towards the ground, neglecting air resistance.
It is 0.1 metre per second-squared.
The acceleration due to the earths gravitational field at the surface is on average about 9.8 m/s^2, or 9.8 meters per second per second. This means that every second you fall go 9.8 m/s faster. So if we ignore air-resistance we find that a rock dropped from rest will have a speed of 3s * 9.8 m/s^2 = 29,4 m/s.
1.63 m/s2
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2