x the length of the shorter piece 3·x the length of the longer piece x + 3·x the length of the whole board = 4·x = 76" x = 76" / 4 = 19.
If a piece of wire was cut into 2 pieces in the ratio 7:8 and the shorter piece was 14cm, then the length of the longer piece will 16cm.
piece a has a greater length than piece b (a>b)
4 parts
Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.
If the original meterstick was broken into two pieces, and one piece is 54 cm long, then the other piece would be the total length of the meterstick (100 cm) minus the length of the first piece. Therefore, the length of the other piece would be 100 cm - 54 cm = 46 cm.
x the length of the shorter piece 3·x the length of the longer piece x + 3·x the length of the whole board = 4·x = 76" x = 76" / 4 = 19.
If a piece of wire was cut into 2 pieces in the ratio 7:8 and the shorter piece was 14cm, then the length of the longer piece will 16cm.
piece a has a greater length than piece b (a>b)
I think 9 and 3... no, its 5 and 7.
If 104 yards of ribbon is cut into 14 equal length pieces, each piece will have length of 7.43 yards, to the justified number of significant digits.
4 parts
Let x be the length measure of the shortest piece of wood, and 3x the length measure of the other piece of wood. So we have: x + 3x = 8 4x = 8 divide by 4 to both sides; x = 2 The length measure of the shortest piece of wood is 2.
Longer: 6.75ft Shorter: 6.25ft
Let the length of the shorter piece be x feet. Therefore, the length of the longer piece would be x + 1 feet. Since the total length of the ribbon is 9 feet, we can write the equation x + (x + 1) = 9. Solving this equation, we find that the shorter piece is 4 feet long and the longer piece is 5 feet long.
Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.
1.5115