The initial velocity is zero.
In most basic physics problems like this one the initial velocity will be zero
as a rule of thumb:
the initial velocity is always zero, unless otherwise stated, or this is what you are solving for
Cases where the initial velocity is not zero
examples
a cannon ball is shot out of a cannon at 50 mph
a ball is thrown from at a speed of 15 mph
etc
Acceleration = Final velocity - Initial velocity / time
This is a velocity question so u need to use uvaxt
Well, (final velocity) = (initial velocity) + (acceleration x time)
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
If the velocity is constant, thenDisplacement = (initial velocity) multiplied by (time)
The velocity versus time graph would be a straight line sloping downward. The velocity would start at 0 when the object is released, then increase linearly in the negative direction as it accelerates due to gravity.
If you simply release an object, the initial velocity is always zero.
A ball thrown straight will curve downward due to the pull of gravity acting on it. As the ball moves forward, gravity exerts a downward force on it, causing it to follow a curved path towards the ground. This downward curve is influenced by factors such as air resistance and the initial velocity and angle at which the ball was thrown.
When a ball is dropped, it starts with an initial velocity of zero. However, as it falls towards the ground, it accelerates due to gravity, causing its velocity to increase. Therefore, the velocity of the ball is non-zero as it falls towards the ground.
Yes, uniform negative acceleration (specifically gravity) can accurately describe the motion of a heavy object thrown downward from a tall building. The object would experience a constant acceleration due to gravity as it falls towards the ground. This acceleration would cause the object's velocity to increase over time until it reaches the ground.
The height from which an object is dropped does not affect its average velocity. Average velocity depends on the overall displacement and time taken to achieve that displacement, regardless of the initial height of the object.
Acceleration = Final velocity - Initial velocity / time
If air resistance can be neglected, the acceleration of a ball tossed straight upward is the same as when it is dropped - both experience a gravitational acceleration of 9.81 m/s^2 downward. The initial velocity of the tossed ball would cause it to momentarily counteract the acceleration and then eventually slow down and reverse direction due to gravity.
The vertical component of velocity for the projectile when it is fired horizontally is zero. This is because the initial velocity is entirely in the horizontal direction, and there is no initial velocity in the vertical direction. Gravity will act on the projectile, causing its vertical velocity to increase as it travels.
The bomb will fall vertically downward relative to the plane as both the bomb and the plane are in motion. The horizontal distance between the bomb and the plane will increase as the bomb falls due to the plane's forward velocity.
20.40
The formula for linear acceleration is a (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. This formula is used to calculate the rate of change of velocity in a straight line motion by finding the difference between the final and initial velocities and dividing by the time taken to change velocity.