Five or less fire calls is: P(0)+P(1)+......+P(5). Formula is: P(x) = (mxe-m)/x! where m=mean & x is number of calls So, P(o) = (3.40e-3.4)/0! = .0334 Likewise P(1)=.1135; P(2)=.1929; P(3)=.2186; P(4)=.1858 & P(5)=.1264. So, P(Five or less fire calls) = .8706
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
Assuming the uniform continuous distribution, the answer is 29/49. With the uniform discrete distribution, the answer is 29/50.
It is approx 0.8312
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
Assuming that "piossion" refers to Poisson, they are simply different probability distributions that are applicable in different situations.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
Assuming you mean random variable here. A random variable is term that can take have different values. for example a random variable x that represent the out come of rolling a dice, that is x can equal 1,2,3,4,5,or 6. Think of probability distribution as the mapping of likelihood of the out comes from an experiment. In the dice case, the probability distribution will tell you that there 1/6 the time you will get 1, 2,3....,or 6. this is called uniform distribution since all the out comes have that same probability of occurring.
Assuming the uniform continuous distribution, the answer is 29/49. With the uniform discrete distribution, the answer is 29/50.
It is approx 0.8312
Assuming that you are considering a N(0,1) Gaussian distribution, the answer is approximately 1 in 20. The 0.95%ile (two tailed) occurs at -1.96 and 1.96.
The answer will depend on the underlying distribution, which is not specified. The normal distribution, although often used at school is not really appropriate because it allocates a positive probability to the event that the lifespan is negative. That is clearly an impossible event! A more appropriate distribution is often the lognormal.Anyway, assuming that you are of school age, and therefore assuming a normal distribution,P(Lifespan < 136) = 0.37P(Lifespan > 150) = 0.20
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
Assuming that "piossion" refers to Poisson, they are simply different probability distributions that are applicable in different situations.
assuming that it is a regular die with numbers 1-6 on them the probability is 1
Assuming that the colors are balanced, the probability is 1 in 5.
assuming a single six sided die the probability of rolling a three is 1/6
Assuming that you mean David Beckham, the probability is very close to 0.