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If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).
ab = 4x + 8
bc = 8x + 4
ac = 18x - 11
b = a/(4x + 8)
c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]
c = a/(18x - 11)
a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:
(4x + 8)(8x + 4) = (18x - 11)
32x^2 + 16x + 64x + 32 = 18x - 11
32x^2 + 62x + 43 = 0
x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]
x = [-62 ± √(-1660)]/64
x = [-62 ± i√(1660)]/64
x = -62/64 ± i√(1660/4096) (64^2 = 4096)
x = -31/32 ± i√[415/1024]
Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.
ab = 4x + 8
bc = 8x + 4
ac = 18x - 11
What else can I help you with?
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