√(2x^2)
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If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
Suppose the other leg is x. Then the hypotenuse is x+2 So, by Pythagoras, (x+2)2 = 82 + x2 or, x2 + 4x + 4 = 64 + x2 so 4x = 60 so x = 15 and the hypotenuse is 17
24.25
The hypotenuse leg of a right angle triangle is its longest side.
Short leg = x Long leg = x times the square root of 3 Hypotenuse = 2x