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So in this case, what you want to do is substitute in the value of 5 everywhere there is an x in the function.

Since:

f(x) = 3x + 2

And we know what x equals (5), You would solve for f(5) with:

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

So y = 17. (Remember that f(x) is another notation for y)

So, since x = 5, and y = 17, the ordered pair is: (5, 17)

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Q: If f(x) 3x plus 2 find f(5) and give the ordered pair.?

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f(2) = -2 + 12 = 10 so the ordered pair is (-2, 10).

(0, 6)

There is not "the ordered pair" but infinitely many ordered pairs which, taken together, comprise the straight line defined by the equation.

There is not "the ordered pair" but infinitely many ordered pairs which, taken together, comprise the straight line defined by the equation.

There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.

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f(2) = -2 + 12 = 10 so the ordered pair is (-2, 10).

The ordered pair is (1, 3).

(0, 6)

There is not "the ordered pair" but infinitely many ordered pairs which, taken together, comprise the straight line defined by the equation.

There are an infinite number of ordered pairs. (-5, -7) is one pair

No real roots.

The ordered pair is (1, 1).

There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.

It depends very much on what the question is!

1,3 if the x term comes first; 3,1 if the y term comes first.

f(x)= 3x+2 x=5f(5)=3(5)+2f(5)=17y=17(5,17)