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fx=5x1 / 9
f(x) = x2 + 5x + 6At a critical point, f'(x) = 0.f'(x) = 2x + 5 = 02x = -5x = -2.5f(-2.5) = (-2.5)2 + 5(-2.5) + 6 = (6.25) - (7.5) + (6) = 4.75
If f(x)=(5x-1)/9 Then the inverse is x=(5y-1)/9 9x=5y-1 9x+1=5y (9x+1)/5=y The inverse is f(x)=(9x+1)/5
If you are talking about f(x) then yes it is the same as y
If there is a remainder then it's not a factor otherwise yes