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How do you tell if lines are perpendicular based on slope?
The slope (rise over run) of one line will be a number (n) or (-n) and the perpendicular line's slope will be the exact opposite. So, for instance, if one line has a slope of 2/3, then a perpendicular line's slope must be -2/3, and vice versa.
What capitals letters of the alphabet have two perpendicular lines?
N, M and H
What intersecting lines are not perpendicular in the alphabet?
The letters A, K, M, N, R, V, W, Y, and Z all have lines in them that are not perpendicular.
A line segment that extends from a vertex of a triangle to its opposite side and is perpendicular to the side?
A, c u n t
What are the values of m and n given that y plus 4x equals 11 is the perpendicular bisector of the line joining m 2 to 6 n?
y + 4x = 11 so y = -4x + 11 whose gradient is -4. So gradient of line joining the two given points is 1/4. Therefore (n - 2)/(6 - m) = 1/4 or 4*(n - 2) = 6 - m that is 4n + m = 14 Also, the given line passes through the midpoint, [(m+6)/2, (2+n)/2] so (2+n)/2 + 4*(m+6)/2 = 11 multiply through by 2 and simplify: 2 + n + 4m + 24 = 22 that is n + 4m = -4 Solving the two equations gives m = -2 and n = 4 4n + m = 14 -4(n + 4m = -4) 4n + m = 14 -4n - 16m = 16 add both equations -15m = 30 divide by -15 m = -2 Substitute m with -2 into n + 4m = -4. n - 8 = -4 add 8 to both sides n = 4 Answer: If the slope or gradient is 1/4 then m = -2 and n = 4 because (2-4)/(-2-6) = 1/4 The lines coordinates are (-2, 2) and (6, 4) and its equation is 4y = x + 10
what- line m is perpendicular to line L, line n is perpendicular to line m.?
Line L is parallel to line n.
Line n is perpendicular to line m. Line l is perpendicular to line m. Is it possible for line n and line l to be skew?
No. It's impossible. There's a corollary that states: If two lines are perpendicular to the same line, then the two lines are parallel.
What is the formula for moment of a force?
Turning moment (Nm) = Force (N) x Perpendicular Distance from the pivot to the line of action of the force (m)
How do you tell if lines are perpendicular based on slope?
The slope (rise over run) of one line will be a number (n) or (-n) and the perpendicular line's slope will be the exact opposite. So, for instance, if one line has a slope of 2/3, then a perpendicular line's slope must be -2/3, and vice versa.
What capitals letters of the alphabet have two perpendicular lines?
N, M and H
What intersecting lines are not perpendicular in the alphabet?
The letters A, K, M, N, R, V, W, Y, and Z all have lines in them that are not perpendicular.
How many letters of the alphabet have perpendicular line segments?
The answer to this probably depends on (a) the font and (b) wheter the uppercase letter or the lowercase letters are considered. In this particular font, in uppercase B D E F H I K L M N P R and T all have perpendicular segments, G has a short perpendicular segment J has a perpendicular segment which ends in a curve U has two perpendicular segments joined by a curve and in lowercase b d h i k l m n p r and u all have perpendicular segments a f g j and t all have perpendicular segments with curved parts.
What is the relationship between the values m and n plotted on the number line?
what is the relationhip between the values m and n plotted on the number line
A line segment that extends from a vertex of a triangle to its opposite side and is perpendicular to the side?
A, c u n t
Which letters in the alphabet contain parallel and perpendicular lines?
The letters in the alphabet that contain parallel lines are "H," "I," "K," "N," "X," and "Z." These letters have two or more straight lines that run alongside each other without intersecting. The letter "T" also contains perpendicular lines, as it has one vertical line intersected by a horizontal line at a right angle.
What are the values of m and n given that y plus 4x equals 11 is the perpendicular bisector of the line joining m 2 to 6 n?
y + 4x = 11 so y = -4x + 11 whose gradient is -4. So gradient of line joining the two given points is 1/4. Therefore (n - 2)/(6 - m) = 1/4 or 4*(n - 2) = 6 - m that is 4n + m = 14 Also, the given line passes through the midpoint, [(m+6)/2, (2+n)/2] so (2+n)/2 + 4*(m+6)/2 = 11 multiply through by 2 and simplify: 2 + n + 4m + 24 = 22 that is n + 4m = -4 Solving the two equations gives m = -2 and n = 4 4n + m = 14 -4(n + 4m = -4) 4n + m = 14 -4n - 16m = 16 add both equations -15m = 30 divide by -15 m = -2 Substitute m with -2 into n + 4m = -4. n - 8 = -4 add 8 to both sides n = 4 Answer: If the slope or gradient is 1/4 then m = -2 and n = 4 because (2-4)/(-2-6) = 1/4 The lines coordinates are (-2, 2) and (6, 4) and its equation is 4y = x + 10
What is alternate interior angles?
Let be a set of lines in the plane. A line k is transversal of if # , and # for all . Let be transversal to m and n at points A and B, respectively. We say that each of the angles of intersection of and m and of and n has a transversal side in and a non-transversal side not contained in . Definition:An angle of intersection of m and k and one of n and k are alternate interior angles if their transversal sides are opposite directed and intersecting, and if their non-transversal sides lie on opposite sides of . Two of these angles are corresponding angles if their transversal sides have like directions and their non-transversal sides lie on the same side of . Definition: If k and are lines so that , we shall call these lines non-intersecting. We want to reserve the word parallel for later. Theorem 9.1:[Alternate Interior Angle Theorem] If two lines cut by a transversal have a pair of congruent alternate interior angles, then the two lines are non-intersecting.Figure 10.1: Alternate interior anglesProof: Let m and n be two lines cut by the transversal . Let the points of intersection be B and B', respectively. Choose a point A on m on one side of , and choose on the same side of as A. Likewise, choose on the opposite side of from A. Choose on the same side of as C. Hence, it is on the opposite side of from A', by the Plane Separation Axiom. We are given that . Assume that the lines m and n are not non-intersecting; i.e., they have a nonempty intersection. Let us denote this point of intersection by D. D is on one side of , so by changing the labeling, if necessary, we may assume that D lies on the same side of as C and C'. By Congruence Axiom 1 there is a unique point so that . Since, (by Axiom C-2), we may apply the SAS Axiom to prove thatFrom the definition of congruent triangles, it follows that . Now, the supplement of is congruent to the supplement of , by Proposition 8.5. The supplement of is and . Therefore, is congruent to the supplement of . Since the angles share a side, they are themselves supplementary. Thus, and we have shown that or that is more that one point, contradicting Proposition 6.1. Thus, mand n must be non-intersecting. Corollary 1: If m and n are distinct lines both perpendicular to the line , then m and n are non-intersecting. Proof: is the transversal to m and n. The alternate interior angles are right angles. By Proposition 8.14 all right angles are congruent, so the Alternate Interior Angle Theorem applies. m and n are non-intersecting. Corollary 2: If P is a point not on , then the perpendicular dropped from P to is unique. Proof: Assume that m is a perpendicular to through P, intersecting at Q. If n is another perpendicular to through P intersecting at R, then m and n are two distinct lines perpendicular to . By the above corollary, they are non-intersecting, but each contains P. Thus, the second line cannot be distinct, and the perpendicular is unique. The point at which this perpendicular intersects the line , is called the foot of the perpendicular
