Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case).
Area of a equilateral triangle is: (side length^2*√3)/4
Each triangle is of area: 62.353829072479572 inches square.
62.353829072479572*6 = 374.12297443487743 inches square approx.
Length of one side = 114/6 inches = 19 inches
If the perimeter of the hexagon is 72, then each side of the hexagon is 72/6 = 12. Therefore, one side of the square is also 12, since the hexagon and the square share a side, so the area of the square is 12 x 12 = 144 cm.
It is not possible to answer a question given only the length of one side of a hexagon unless we are told it is a regular hexagon. I added a link that lets you calculate areas of regular polygons.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
P = 6(5/8 inches) =
9 inches
Length of one side = 114/6 inches = 19 inches
The area is 166.3 square inches.
The side length is 6.20403 units.
If the perimeter of the hexagon is 72, then each side of the hexagon is 72/6 = 12. Therefore, one side of the square is also 12, since the hexagon and the square share a side, so the area of the square is 12 x 12 = 144 cm.
This hexagon is made of 6 equilateral trianges of side length 8 inches. Height of such a triangle is SQRT(8^2 - 4^2) = SQRT(48) = 6.93 inches. Area of one triangle = 4 x 6.93 = 27.71 square inches. Answer = 6 * 27.71 = 166.28 square inches
It is not possible to answer a question given only the length of one side of a hexagon unless we are told it is a regular hexagon. I added a link that lets you calculate areas of regular polygons.
Length of one side squared x 1.5 x square root of 3, for a REGULAR hexagon.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
A square with a side length of 6 inches has an area of 36 square inches.
P = 6(5/8 inches) =
if perimeter is 228 inches then each side is 228/6 = 38 inches since haxagon has 6 equal sides