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Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case).
Area of a equilateral triangle is: (side length^2*√3)/4
Each triangle is of area: 62.353829072479572 inches square.
62.353829072479572*6 = 374.12297443487743 inches square approx.
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What is the length of one side of a regular hexagon if its perimeter is 114 inches?
Length of one side = 114/6 inches = 19 inches
If a regular hexagon shares a side with a square and the perimeter of the hexagon is 72 cm what is the area of the square?
If the perimeter of the hexagon is 72, then each side of the hexagon is 72/6 = 12. Therefore, one side of the square is also 12, since the hexagon and the square share a side, so the area of the square is 12 x 12 = 144 cm.
What is the area of a hexagon if one side is 5cm?
It is not possible to answer a question given only the length of one side of a hexagon unless we are told it is a regular hexagon. I added a link that lets you calculate areas of regular polygons.
If s 8 inches and a 1.3 find the area of the regular hexagon. Round the answer to one decimal place.?
s = 8 and a = 1.3 are not compatible for a regular hexagon.
What is the formula for a regular hexagon with one side five eighths of an inch?
P = 6(5/8 inches) =
