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P = 4*a (a is side length) Area = p*q/2 (p=perimeter, q=diagonal
Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet
A sphere, of radius a = 11.4 cm and charge q = 5.00 × 10 − 6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 26.2 cm and outer radius c = 28.2 cm . This shell has a net charge of -q. visit our page : grandarchinex.co.in
If the two axes intersect at the point (p, q), then the equation is: (x -p)2/25 + (y - q)2/9 = 1
Since you know that it is a parallelogram (not parallellogram!) you already know that the opposite sides are mutually parallel. All you need to do is to establish that any pair of adjacent sides are of equal length, or equivalently, the squares of these lengths are equal. The squared length of the line AB where A = (p,q) and B = (r,s) is (p - r)^2 + (q - s)^2.