The answer depends on what the lengths s and a are meant to represent.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
4.5
To find the area of a regular hexagon with a side length of ( s = 8 ) inches, we can use the formula ( \text{Area} = \frac{3\sqrt{3}}{2} s^2 ). Plugging in the value, we get: [ \text{Area} = \frac{3\sqrt{3}}{2} (8^2) = \frac{3\sqrt{3}}{2} \times 64 = 96\sqrt{3} \approx 166.3 \text{ square inches} ] Thus, the area of the hexagon, rounded to one decimal place, is approximately ( 166.3 ) square inches.
The perimeter of a hexagon is the sum of its 6 sides.
If the circumference of the circle is 2.5 inches then its diameter is 2.5/pi = 0.796 of an inch rounded up to 3 decimal places
s = 8 and a = 1.3 are not compatible for a regular hexagon.
The area is 166.3 square inches.
166.30
166.30
4.5
To find the area of a regular hexagon with a side length of ( s = 8 ) inches, we can use the formula ( \text{Area} = \frac{3\sqrt{3}}{2} s^2 ). Plugging in the value, we get: [ \text{Area} = \frac{3\sqrt{3}}{2} (8^2) = \frac{3\sqrt{3}}{2} \times 64 = 96\sqrt{3} \approx 166.3 \text{ square inches} ] Thus, the area of the hexagon, rounded to one decimal place, is approximately ( 166.3 ) square inches.
It's regular, it has 6 sides and each side is 8.2 inches. Wrap a wet towel round your head and I'm sure you'll be able to work it out.
The question was extremely poorly worded since it gave no information on what S and a were. However, having figured that out, the answer is 166.3 square units.
10.4 cm
It is 679 square metres.
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
A hexagon can be drawn either with a compass or round object, or free hand. A hexagon has six equal sides and six equal angles. For a perfect hexagon, a compass is recommended. * * * * * While a hexagon does have six sides and six vertices, these need not be equal. If the sides are all equal AND the angles are equal, then the hexagon is a regular hexagon.