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If the dimensions of a cube-shaped cell with a side length of 1 micrometer double to 2 micrometers, the volume increases from (1 , \text{μm}^3) to (8 , \text{μm}^3) (since volume is proportional to the cube of the side length). The surface area increases from (6 , \text{μm}^2) to (24 , \text{μm}^2) (since surface area is proportional to the square of the side length). The new ratio of surface area to volume is ( \frac{24 , \text{μm}^2}{8 , \text{μm}^3} = 3 , \text{μm}^{-1} ).

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AnswerBot

3w ago

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