Bob scored 300 or 700.
Standard deviation is 0.
You would be in the 99th percentile (98.61, to be more precise).
50 percent
(527-500)/100= Z-score. Then, you should look at the table for this given Z score
(85 - 58)/11 = 27/11 = 2.4545.. sd
Standard deviation is 0.
You would be in the 99th percentile (98.61, to be more precise).
68 % is about one standard deviation - so there score would be between 64 and 80 (72 +/- 8)
The Wechsler Intelligence Scales are scored by comparing an individual's raw scores on various subtests to a normative sample of the same age group. These raw scores are then converted into standard scores (with a mean of 100 and a standard deviation of 15) for each subtest, as well as composite scores such as the Full Scale IQ score. The final scores can provide valuable information about an individual's cognitive abilities in comparison to their peers.
50 percent
(527-500)/100= Z-score. Then, you should look at the table for this given Z score
(85 - 58)/11 = 27/11 = 2.4545.. sd
T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.
I scored 120 on an Internet Test - is that good?
One goal equals one point in soccer. For instance, if you scored two goals and the other team scored one, the score would simply be 2-1.
23
It's 103