The hypotenuse is 13.
The other leg length is 16.
third leg 5, area 30
Hypotenuse = 24
Use Pythagoras' theorem: 202-122 = 256 Square root of 256 =16 Length of the other leg is 16 units.
Using Pythagoras' theorem for a right angle triangle the other leg is 3 times the square root of 7
If 8 is a leg and 12 is the hypotenuse, the other leg is: 8.944
A right triangle has a hypotenuse of 13 cm and one leg that measures 12 cm What is the length of the other leg?
The hypotenuse is 15, because in a right triangle the biggest side of it is the hypotenuse. hypotenuse^2 = side^2 + side^2 substitute what you know into the formula; 15^2 = 12^2 + side^2 subtract 12^2 to both sides; 15^2 - 12^2 = side^2 81 = side^2 square both sides and ignore the negative value because the length is positive; 9 = side Thus, the other leg is 9.
A right triangle has a hypotenuse of 12cm and a leg that is 9cm the other leg would be 7.94. This is a math problem.
The other leg length is 16.
a^2 + b^2 = c^2. Therefore, the hypotenuse is (5^2 + 12^2)^1/2
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
Using Pythagoras: 5 cm
The hypotenuse is: 12
third leg 5, area 30
The square root of 217
9