find the slop of the line passing through (1,5) and (0,2)
Points: (1, 5) and (0, 2) Slope: 3
Points: (1, 5) and (0.2)Slope: 3
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2
To find the slope of the line passing through the points (1, 5) and (0, 2), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the coordinates, we have ( m = \frac{2 - 5}{0 - 1} = \frac{-3}{-1} = 3 ). Therefore, the slope of the line is 3.
Slope = (8 - 0)/(0 - 4) = -2
-7/6
Points: (1, 5) and (0, 2) Slope: 3
Points: (1, 5) and (0.2)Slope: 3
If you mean points of: (5, 4) and (0, 3) then the slope is 1/5
Points: (6, -3) and (8, 0) Slope: 3/2 or 1.5
Points: (-2, -3) and (4, 0) Slope: (-3-0)/(-2-4) = 1/2
The slope of the line passing through any two points with coordinates x,y and x',y' is (y' - y)/(x' - x). In this instance, the slope is (5 - 4)/(0 - 2) = -1/2 .
To find the slope of the line passing through the points (1, 5) and (0, 2), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the coordinates, we have ( m = \frac{2 - 5}{0 - 1} = \frac{-3}{-1} = 3 ). Therefore, the slope of the line is 3.
Calculate the slope as (difference of y-coordinates) / (difference of x-coordinates).
It is: y = 5x+6
Slope of line = (change in y coordinates)/(change in x coordinates) = (6-0)/(4-0) = 6/4 = 3/2