If two straight lines are parallel, then their gradients must be equal.
In the form y = mx + c, m is the gradient (and c is the intercept with x=0, the y-axis), so rearrange both of these into this form:
3x - 2y +3 = 0 ->
2y = 3x + 3
y = (3/2)x + 3/2
Kx +5y = 1 ->
5y = -Kx +1
y = (-k/5)x +1/5
As the lines are parallel, the gradients must be equal, that is:
3/2 = -k/5
and so k can be found by solving:
k/5 = -3/2
k = 5 x -3 / 2 = -15 / 2 = -7.5
meaning 3x - 2y + 3 = 0 is parallel to -7.5x +5y = 1 (or 5y - 7.5x = 1 writing y first).
They are: x and y and the expression can be simplified to 6xy
Without an equality sign it is not an equation
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
I will assume that you mean -2xy3+3x2y. Then by "degree" is usually meant the total degree--the maximum sum of exponents of all variables. Here the first term has degree 1+3=4 and the second term has degree 2+1=3, so the degree of the entire expression is 4. It is also a 2nd degree expression in x and a 3rd degree expression in y.
(3 * 3)(2 * 5) (9)(10) 90
They are: x and y and the expression can be simplified to 6xy
3x2y
12
It is a polynomial in x and y.
The GCF is 3x2y
Without an equality sign it is not an equation
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
3x2y - 4xy + 4x
2y-6=3x2y-3x-6=0-3x-6=-2y3/2x+3=yy-inercept= 3slope= y(2)-y(1)/x(2)-x(1)= 6-3/2-0= 3/2
Say the Question is 3(2y+5) Multiply both terms in the brackets by 3 so (3x2y)+(3x5) = 6y+15
I will assume that you mean -2xy3+3x2y. Then by "degree" is usually meant the total degree--the maximum sum of exponents of all variables. Here the first term has degree 1+3=4 and the second term has degree 2+1=3, so the degree of the entire expression is 4. It is also a 2nd degree expression in x and a 3rd degree expression in y.